Problems on Trains

By Bharat Choudhary -
Problems on Trains transparent vector / raster png


Rule 01. When train passes a pole or a stationary man it should travel the length equal to the length of the train.

Rule 02. When a train passes a platform it should travel the length equal to the sum of the lengths of train and platform.

Rule 03. When two trains are moving in opposite directions their speeds should be added to find the relative speed.

Rule 04. When two trains are moving in the same direction the relative speed will be the difference of their speeds.

Rule 05. Two trains are moving in the same direction at x km/hr and y km/hr (where x > y). If the faster train crosses the slower trains in ‘t’ seconds, then the length of the faster train is given by - [5/18(x-y)*t] metres.

Rule 06. A train running at x km/hr takes t1 seconds to pass a platform. Next it takes t2 seconds to pass a man walking at y km/hr in the opposite direction, then the length of the train is - [5/18(x+y)t2] metres and that of the platform is - 5/18[x(t1-t2)-y(t2)] metres.

Rule 07. Two trains are moving in opposite directions at x km/hr and y km/hr (where x>y), if the faster train crosses a man, travelling in the slower train in t seconds, then the length of the faster train is given by - [5/18(x+y)t] metres.

Rule 08. A train running at x km/hr takes t1 seconds to pass a platform. Next it takes t2 seconds to pass a man walking at y km/hr in the same direction, then the length of the train is - [5/18(x-y)t2] metres and and that of the platform is - 5/18[x(t1-t2)+y(t2)] metres.

Rule 09. L metres long train crosses a bridge of length L1 metres in T seconds. Time taken by the train to cross a platform of L2 metres is given by - {[(LxL1)/(LxL2)]T} seconds.

Rule 10. If L metres long train crosses a bridge or a platform of length L1 metres in T seconds, then the time taken by train to cross a pole is given by - (LxT)/(L+L1) seconds.

Rule 11. Two trains start at the same time from A and B and proceed towards each other at the rate of x km/hr and y km/hr respectively. when they meet it is found that one train has travelled d km more than the other. Then the distance between A and B is - [(x+y)/(x-y)]xd km. or [Distance = Difference in Distance x (Sum of Speeds/Difference in Speeds)].

Rule 12. Two stations A and B are D km apart on a straight line. A train starts from A towards B at x km/hr. t hours later another train starts from B towards A at y km/hr. The time after which the train starting from A will meet the train starting from B is - (D+ty)/(x+y) Hours.

Rule 13. A train passes by a stationary man standing on the platform or a pole in t1 seconds and passes by the platform completely in t2 seconds. If the length of the platform is ‘p’ metres, then the length of the train is - (t1xp)/(t2-t1) metres and the speed of the train is - p/(t2-t1) m/s or Length of the Train = [(Length of the Platform/Difference in Time) x Time taken to cross a pole or a stationary man]; and Speed of the Train = Length of the Platform/Difference in time.



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